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14 November, 12:52

The times it took for 35 loggerhead sea turtle eggs to hatch in a simple random sample are normally distributed, with a mean of 50 days and a standard deviation of 2 days. assuming a 95% confidence level (95% confidence level = z-score of 1.96), what is the margin of error for the population mean? remember, the margin of error, me, can be determined using the formula. 0.06 0.11 0.34 0.66

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  1. 14 November, 14:12
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    We are given the following data

    n = 35

    x = 50

    s = 2

    CI = 95% (z = 1.96)

    The formula for the margin of error is

    E = z s / √n

    Substituting the given values

    E = 1.96 (2) / √35)

    E = 0.66 or 66%
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