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31 October, 08:28

2x-4y=8 3x+8y=-2 solve using elimination

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Answers (2)
  1. 31 October, 10:55
    0
    2x+5y=13 multiply both sides by 3

    6x + 15y = 39

    3x - 4y = 8 multiply both sides by - 2

    -6x + 8y = - 16 add the two new equations to each other

    (-6x + 8y) + (6x + 15y) = 39 + (-16)

    -6x + 6x + 8y + 15y = 39 - 16

    0x + 23y = 23

    23y = 23

    y = 1

    2x + 5y = 13 sub in 1 for y

    2x + 5 (1) = 13

    2x + 5 = 13

    2x = 8

    x = 4

    answer (4,1)

    check:

    3 (4) - 4 (1) = 8

    12 - 4 = 8

    8 = 8
  2. 31 October, 11:21
    0
    2 (2x-4y=8) = 4x-8y = 16

    3x+8y=-2

    4x-8y=16

    3x+8y=-2

    the 8s cancel out

    4x+3x = 14

    7x=14

    x=2

    2 (2) - 4y = 8

    4-4y = 8

    -4 - 4

    -4y=4

    y=-1

    x=2

    y=-1

    (2,-1)
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