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2 January, 14:59

Use the quadratic formula to solve 2y2 + 2y - 12 = 0.

Question 6 options:

{-3, - 2}

{3, - 2}

{-3, 2}

{3, 2}

+3
Answers (1)
  1. 2 January, 17:31
    0
    Hello

    y²+y-6=0

    ==> y²-2y+3y-6=0

    ==>y (y-2) + 3 (y-2) = 0

    ==>y-2) (y+3) = 0

    ==>y=-3 or y=2

    Answer C (-3,2)
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