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16 September, 19:44

Five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find their present ages

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  1. 16 September, 20:59
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    Father = x

    son = y

    x-5 = 7 (y-5)

    x + 5 = 3 (y+5) solve the system

    x-5 = 7y-35

    x+5 = 3y + 15

    x-5 = 7y-35

    -x-5 = - 3y - 15

    -10 = 4y - 50

    +50 + 50

    40 = 4y

    10 = y

    Solve for X

    x+5 = 3 (10) + 15

    x+5 = 45

    x = 40

    The father is 40yrs old and the son is 10yrs old.
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