The sum of three consecutive integers is 126 ...

The three consecutive integers are: x, (x+1) and (x+2).

We can suggest this equation:

x + (x+1) + (x+2) = 126

3x+3=126

3x=126-3

3x=123

x=123/3

x=41

x=41

(x+1) = 41+1=42

(x+2) = 41+2=43

Answer: the three consecutive integers would be: 41,42 and 43.