Given that f (x) = x^2 - 3x 6 and g (x) = x-3/2 solve for f (g (x)) when x = 1

If you would like to solve for f (g (x)) when x = 1, you can do this using the following steps:

f (x) = x^2 - 3x + 6

g (x) = x - 3/2

f (g (x)) = f (x - 3/2) = (x - 3/2) ^2 - 3 * (x - 3/2) + 6

x = 1

f (g (1)) = f (1 - 3/2) = f (-1/2) = (-1/2) ^2 - 3 * (-1/2) + 6 = 1/4 + 3/2 + 6 = 1/4 + 6/4 + 24/4 = 31/4 = 7 3/4

The correct result would be 7 3/4.