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3 September, 04:41

Given the equations 2x + 2y = 16 and 4x - 3y = - 3, what are the values of x and y?

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  1. 3 September, 06:53
    0
    Steps:

    1. Put 2x + 2y=16 into slope-intercept form

    2. Subtract 2x on both sides

    2y = - 2x + 16

    3. Divide by 2 on both sides

    Y = - x + 8

    4. Substitute the y in 4x - 3y=-3 for - x + 8

    4x - 3 (-x + 8) = - 3

    5. Multiply everything in parentheses

    4x + 3x + (-24) = - 3

    7x + (-24) = - 3

    6. Add 24 on both sides

    7x=21

    7. Divide by 7

    8. X = 3

    9. Substitute the x for a 3 in one of the equations

    Y=-x + 8

    Y = - 3 + 8

    Y=5

    10. Your answers are

    X = 3 Y = 5
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