Deshawn has several dimes and quarters that total $2.05. he has 3 fewer quarters than dimes. how many of each doe he have

Let

x = the number of dimes

y = the number of quarters

The total sum is $2.05, therefore

0.10x + 0.25y = 2.05

Divide through by 0.05 to obtain

2x + 5y = 41 (1)

There are 3 fewer quarters than dimes, therefore

y = x - 3 (2)

Substitute (2) into (1).

2x + 5 (x - 3) = 41

2x + 5x - 15 = 41

7x = 56

x = 8

y = x - 3 = 5

Answer: 8 dimes, 5 quarters