Solve 2x2 - 12x + 20 = 0.

3 ± i

3 ± 2i

1 ± 2i

2 ± 3i

This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:

x=[-b+/-sqrt (b^2-4ac) ] / (2a)

from our equation, a=2, b=-12 and c=20

x=[ - (-12+/-sqrt ((-12) ^2-4*2*20) ] / (2*2)

x=[12+/-sqrt (144-160]/4

x=[12+/-sqrt (-16) ]/4

x=[12+/-4i]/4

x=[3+/-i]

the answer is A] 3+/-i