Ask Question
21 September, 19:23

Three women and three children wish to cross a river in a canoe that will hold only one woman and or two children. they can all row on their own but no one can swim. if a onne way trip in the canoe takes ten minutes, what is the minimum time in which all six people can cross the river

+2
Answers (1)
  1. 21 September, 19:57
    0
    (w, k)

    that is amount of women and children lefton original side

    ok, first realize you must get children across first because who will row the boat back

    first trip: 10min, 2 children across, (3,1)

    2nd trip: 20min, 1 kid cross back (3,2)

    3rd trip: 30min, 2 kids cross (3,0)

    4th trip: 40 min, 1 kid cross baack (3,1)

    5th trip: 50 min, 1 woman cross (2,1)

    6th trip: 60 min, 1 kid cross back (2,2)

    7th trip: 70 min, 1 woman cross (1,2)

    8th trip: 80 min, 1 kid cross back (1,1)

    9th trip: 90 min, 1 woman cross (0,1)

    10th trip: 100min, 1 kid cross back (0,2)

    11th trip: 110 min, 2 kids cross back (0,0)

    min time is 110 mins or 1hr 50min
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Three women and three children wish to cross a river in a canoe that will hold only one woman and or two children. they can all row on ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers