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9 August, 08:52

What is the axis of symmetry f (x) = x^2-8x+32

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  1. 9 August, 11:37
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    The axis of symmetry is 2

    2x^2-8x+8

    2 (x^2-4x) + 8

    2 (x-2) ^2-2 (4) + 8

    2 (x-2) ^2-8+8

    2 (x-2) ^2

    ^ on a graph would be at x=2
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