Simplify the question With Steps

i^50 (It is iota with 50. as an exponent)

There's no way to begin until we know the value of ' i '.

If ' i ' doesn't represent √-1, then we can stop here

and discard the question as unanswerable.

If ' i ' is the famous √-1, then here's how i⁵⁰ can be simplified:

Notice the following:

- - The 1st power of i is √-1.

- - The 2nd power of i is (√-1) ² = - 1

- - The 3rd power of i is - √-1

- - The 4th power of i is (-√-1) · (√-1) = - (-1) = 1.

- - Every 4 powers of ' i ' brings you back to ' 1 '.

So from the exponent of 50, you can knock out

the largest possible multiple of 4, and evaluate

what's left.

50 = 48 + 2

i⁵⁰ = i² = - 1.

steps. convert it to a positive exponent

then evaluate the exponent

then flip the fraction