Ricardo and John start swimming from the same location. Ricardo starts 15 seconds before John and swims at a rate of 3 feet per second. John swims at a rate of 4 feet per second in the same direction as Ricardo. which equation could you solve to find how long it would take John to catch up with Ricardo?

A. 4t+3=3t

B. 4t+60=3t

C. 3t+3=4t

D. 3t+45=4t

Question

Mathematics

Kianna Patrick

11 May, 14:04

Ricardo and John start swimming from the same location. Ricardo starts 15 seconds before John and swims at a rate of 3 feet per second. John swims at a rate of 4 feet per second in the same direction as Ricardo. which equation could you solve to find how long it would take John to catch up with Ricardo?

A. 4t+3=3t

B. 4t+60=3t

C. 3t+3=4t

D. 3t+45=4t

+1

Answers (1)

Know the Answer?

Parker Key · Answer 1

Speed=distance / time; ⇒distance=speed * time

Distance traveled by Ricardo

Distance (Ricardo) = (3 ft / s) * 15s+3 ft/s * time=45 ft+3 ft/s*t=45+3t

Distance traveled by John:

Distance (John) = (4 ft/s) * time=4t

Distance traveled by Ricardo=Distance traveled by John

3t+45=4t

Answer: D. 3t+45=4t