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25 June, 10:26

Determine the sum: (14abc2 + 12a2b + 16b2c) + (-3abc2 + 2b2c).

11abc2 + 12a2b + 18b2c

11a2b2c4 + 12a2b + 18b4c2

41a4b7c6

42a3b4c3 - ab3c3

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  1. 25 June, 11:16
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    The answer is 11abc^2 + 12a^2b + 18b^2c because:

    14abc^2-3abc^2 is 11abc^2

    12a^2b + 0 = 12a^2b

    16b^2c + 2b^2c = 18b^c
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