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27 January, 19:14

Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile and others are not marked. The probabilities are displayed in the table below:

| Red |Green |Brown

Smile |0.100 |.300 |.10

No smile |0.200 |.150 |.15

If a random candy is chosen from this bag, what is the probability that the candy was red or had no smile?

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Answers (2)
  1. 27 January, 20:34
    0
    | Red |Green | Brown Total

    Smile |0.100 |.300 |.10 0.50

    No smile |0.200 |.150 |.15 0.50

    Total 0.30 0.45 0.25 1.00

    The probability of choosing red candy is 0.10

    The probability of choosing no smile candy is 0.50

    The probability of choosing red or no smile = 0.10 + 0.50 = 0.60

    I did not use 0.30 as the probability of red because it included the no smile candy. It should only be red candy that has a smile.
  2. 27 January, 21:18
    0
    The correct answer is:

    A: 0.60
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