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4 April, 20:53

There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45 homes. Each year, 3 new homes are built in Neighborhood B.

Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years.

Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years?

Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically.

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Answers (2)
  1. 4 April, 22:18
    0
    A.

    this is assuming it grows by 20% of the houses it has at that time (compound interest)

    A (x) = 30 (1.2) ˣ⁻¹ or A (x) = 25 (1.2) ˣ

    B (x) = 3 (x-1) + 45 or B (x) = 3x+42

    B.

    A (5) = 62.28 or about 62 homes

    B (5) = 60

    C.

    this is tricky so I think it should have been only 20% of 30

    start over

    A.

    20% of 30=6

    A (x) = 6 (x-1) + 30 or A (x) = 6x+24

    B (x) = 3 (x-1) + 45 or B (x) = 3x+42

    B.

    A (5) = 54 homes

    B (5) = 60

    C.

    6x+24=3x+42

    minus 3x

    3x+24=42

    minus 24 both sides

    3x=18

    divide by 3

    x=6

    after 6 years

    both will have 63 homes
  2. 5 April, 00:42
    0
    Part A

    y=number of years (in both equations)

    F (a) = 30 (1+r/n) ^y

    r=.2 (20%)

    n=1

    F (b) = 45 + (3y)

    Part B

    A=74.6496 (personally I'd round to 74 because we are talking about an item that's not complete/useable yet, vs just a number if rounding is even required)

    B=60

    Part C

    y=3.32 or approx 3 and 1/3 years

    solve both and each neighborhood has about 55 houses

    54.95 for a

    54.96 for b
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