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Mathematics
Rylee Gonzalez
22 November, 02:57
Solve for x over the complex numbers. x2+10x+41=0
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Jaiden Yu
22 November, 03:24
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X²+10x+41=0
using x = (-b±√b²-4ac) ½
where a = 1
b=10
c=41
x = (-10±√10²-4*1*41) ½
x=-5 ± √ (100-164)
x=-5±√ (-64) ½
x=-5±4i
x=-5+4i or - 5-4i
where i = √-1
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Gilberto Baird
22 November, 04:17
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The correct answer is X = - 5 ± 41
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