Solve for x over the complex numbers. x2+10x+41=0

Question

Mathematics

Rylee Gonzalez

22 November, 02:57

Solve for x over the complex numbers. x2+10x+41=0

+2

Answers (2)

Know the Answer?

Jaiden Yu · Answer 1

X²+10x+41=0

using x = (-b±√b²-4ac) ½

where a = 1

b=10

c=41

x = (-10±√10²-4*1*41) ½

x=-5 ± √ (100-164)

x=-5±√ (-64) ½

x=-5±4i

x=-5+4i or - 5-4i

where i = √-1

Gilberto Baird · Answer 2

Gilberto Baird 22 November, 04:17

0

The correct answer is X = - 5 ± 41