Jessica is packing her bags for her vacation. She has 9 unique Fabergé eggs, but only 3 fit in her bag.

How many different groups of 3 Fabergé eggs can she take?

The number of different groups can be found by finding 9C3 (Using combinations)

We will find combinations from n = 9 to r = 3

Therefore, 9C3 = 9!/6!*3! = (9*8*7*6!) / (6!*3*2)

= 3*4*7

= 84 ways.