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30 January, 00:42

Let a = (?2,1,2, b = (?1,2,4, and p = (k, k, k. the vector from a to b is perpendicular to the vector from a to p when k =

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  1. 30 January, 02:54
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    Vector a = (2, 1, 2)

    Vector b = (1, 2, 4)

    Vector p = (k, k, k)

    Vector a to vector b = vector b - vector a = (1, 2, 4) - (2, 1, 2) = (1 - 2, 2 - 1, 4 - 2) = (-1, 1, 2)

    Vector a to vector p = vector p - vector a = (k, k, k) - (2, 1, 2) = (k - 2, k - 1, k - 2)

    Vector a to b is perpendicular to vector a to p if the dot product of vector a to vector b and vector a to vector p is equal to zero.

    i. e. (-1, 1, 2). (k - 2, k - 1, k - 2) = 0

    -1 (k - 2) + (k - 1) + 2 (k - 2) = 0

    -k + 2 + k - 1 + 2k - 4 = 0

    2k - 3 = 0

    2k = 3

    k = 3/2
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