What is the inverse of h? h (x) = 6x + 1

A) h-1 (x) = 6x - 1

Eliminate

B) h-1 (x) = 6x + 1

C) h-1 (x) =

x

6

- 1

D) h-1 (x) =

1

--

6

(x - 1)

Question

Mathematics

Averi Miller

29 November, 21:37

What is the inverse of h? h (x) = 6x + 1

A) h-1 (x) = 6x - 1

Eliminate

B) h-1 (x) = 6x + 1

C) h-1 (x) =

x

6

- 1

D) h-1 (x) =

1

--

6

(x - 1)

+1

Answers (1)

Know the Answer?

Connor Conway · Answer 1

The answer is (x-1) / 6. This is found by switching h (x) and x in the original equation, then solving for h (x) (which you can just write as "y" when solving).

What is the inverse of h? h (x) = 6x + 1A) h-1 (x) = 6x - 1EliminateB) h-1 (x) = 6x + 1C) h-1 (x) =x6- 1D) h-1 (x) =1--6(x - 1)

What is the inverse of h? h (x) = 6x + 1

A) h-1 (x) = 6x - 1

Eliminate

B) h-1 (x) = 6x + 1

C) h-1 (x) =

x

6

- 1

D) h-1 (x) =

1

--

6

(x - 1)