What is the solution to the system of equations?

x=3y+5

x-4y=3

(,)

X=3y+5

x-4y=3

3y+5-4y=3

5-y=3

y=5-3

y=2

x=3·2+5

x=6+5

x=11

(2; 11)

So one way is to subsitute

from the first equation we know that x=3y+5

so we subsitte 3y+5 for x in the second equation

(3y+5) - 4y=3

3y+5-4y=3

combine like terms

5-y=3

subtract 5 from both sdies

-y=-2

multiply - 1

y=2

subsitute 2 for y

x=3 (2) + 5

x=6+5

x=11

x=11

y=2

(11,2)