Which factorizations can be used to identify the real zones of the function f (x) = - 20x^2 + 23x-6

For this case we have the following function:

f (x) = - 20x ^ 2 + 23x-6

We can rewrite the function.

For this, we factor.

We have then:

f (x) = - (5x-2) (4x-3)

Therefore, the real solutions are:

x1 = 2/5

x2 = 3/4

Answer:

f (x) = - (5x-2) (4x-3)

x1 = 2/5

x2 = 3/4

-2 (10x^2 + 23*3)

the aswers is: - 2 (10x^2 + 69)