A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?

Question

Mathematics

Jaeden Benson

10 February, 08:42

A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?

+3

Answers (1)

Know the Answer?

Tyrell Barron · Answer 1

To find the 'maximum height' we will need to take the derivative of h (t) = - 16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.

A ball is thrown into the air with an upwardvelocity of 32 ft/s. Its height h in feet after t secondsis given by the function h = - 16t2 + 32t + 6. In howmany seconds does the ball reach its maximumheight? Round to the nearest hundredth if necessary.What is the ball's maximum height?

A ball is thrown into the air with an upward

velocity of 32 ft/s. Its height h in feet after t seconds

is given by the function h = - 16t2 + 32t + 6. In how

many seconds does the ball reach its maximum

height? Round to the nearest hundredth if necessary.

What is the ball's maximum height?