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24 September, 08:58

Five times the sum of three consecutive integers is 150. What are the integers

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Answers (2)
  1. 24 September, 11:43
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    Let x=1st integer

    x+1=2nd integer

    x+2=3rd integer

    5 (x+x+1+x+2) = 150

    5 (3x+3) = 150

    15x+15=150

    15x=135

    x=9

    So you put what x is

    1st integer (x) = 9

    Since it's three consecutive integers, you add one to the 2nd integer

    2nd integer (x+1) = 10

    Then you do the same thing for the third integer

    3rd integer (x+2) = 11
  2. 24 September, 11:52
    0
    5 (x + (x+1) + (x+2)) = 150

    5 (3x+3) = 150

    15x+15=150

    15x=135

    x=9

    Your three consecutive integers are 9, 10, and 11.
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