A spinner is separated into 5 equal pieces, as shown below: patrick spins the spinner 9 times. what is the theoretical probability that it stops on the brown sector on the last spin?

Question

Mathematics

Ashly

12 January, 05:27

A spinner is separated into 5 equal pieces, as shown below: patrick spins the spinner 9 times. what is the theoretical probability that it stops on the brown sector on the last spin?

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Eileen Shepherd · Answer 1

To solve this problem, let us first define what probability means in this case. It would be:

Probability = (number of colors to choose from) / (total number of colors)

There are a total of 5 colors on the spinner. The number of colors to choose from spins 1 to 8 would be 5 out of 5, while for the last spin 9 the number of colors to choose from would only be brown so that would be 1 out of 5. The total probability would be the product of the probability of each spins, therefore:

Probability = 1st spin * 2nd spin * 3rd spin * 4th spin * 5th spin * 6th spin * 7th spin * 8th spin * 9th spin

Probability = (5/5) * (5/5) * (5/5) * (5/5) * (5/5) * (5/5) * (5/5) * (5/5) * (1/5)

Probability = 0.2

There is a 20% chance to get brown on the last spin.