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Mathematics
Miguel Dillon
9 December, 23:09
How do I completely factor 4x^2-64?
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Chuckles
9 December, 23:22
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This is how you will completely factor your equation: 4 (x^2-16)
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Peaches
10 December, 02:26
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4x^2 - 64
= 4 (x + 4) (x - 4)
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