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31 January, 04:13

A mixture of

12%

disinfectant solution is to be made from

10%

and

17%

disinfectant solution. How much of each solution should be used if

28

gallons of the

12%

solution are needed?

+4
Answers (1)
  1. 31 January, 06:03
    0
    Set up a system of 2 equations.

    Gallon equation:

    x+y = 28

    Solution equation:

    10x + 17y = (28) (12)

    Solve with substitution:

    y = 28-x (From 1st equation)

    (Sub into 2nd equation)

    10x + 17 (28-x) = 336

    10x + 476 - 17x = 336

    -7x = - 140

    x = 20

    y = 28-20 = 8

    Therefore the solution is (20,8)

    You need 20 gal of 10% solution mixed with 8 gal of 17% solution to obtain 28 gal of 12% solution.
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