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16 November, 10:01

One of the UK lottery systems consists of selecting six numbers from forty-nine for a one-pound stake. The winning numbers are drawn at random and the order is not important. Determine the probability that a randomly selected set of six numbers will win the lottery.

4.167 * 10-6

8.63 * 10-7

5.467 * 10-6

7.15 * 10-8

Will mark branliest

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  1. 16 November, 12:23
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    As in this problem the order of numbers does not matter We are talking about a combination and not to permutation.

    So to determine the probability that a set of six randomly selected numbers wins the lottery we need to first draw the combination of 6 in 49 without repetition:

    C (49.6) = 49! / (6! (49-6) !) = 13983816

    Then there are 13983816 combinations of possible numbers for this case.

    Finally the probability is:

    p = 1/13983816

    p = 7,151 x10 ^ - 8

    The correct option is the last
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