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8 February, 09:59

If 1 is the zero of polynomial p (x) x2a - 3xa+3x2-1 find the value of a

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  1. 8 February, 11:29
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    The value of a can be obtained by substituting 1 to the equation and equating p (1) = 0.

    p (x) = x2a - 3xa + 3x2 - 1

    p (1) = a - 3a + 3 - 1 = 0

    therefore a = 1

    the equation now becomes p (x) = x2 - 3x + 3x2 - 1
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