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2 July, 21:39

Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers

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  1. 2 July, 23:06
    0
    4 consecutive odd integers ... x, x + 2, x + 4, x + 6

    product of 2 smaller numbers is 64 less then the product of the 2 larger numbers ...

    x (x + 2) = (x + 4) (x + 6) - 64

    x^2 + 2x = (x^2 + 10x + 24 - 64)

    x^2 + 2x = x^2 + 10x - 40

    2x = 10x - 40

    2x - 10x = - 40

    -8x = - 40

    x = - 40/-8

    x = 5

    x + 2 = 5 + 2 = 7

    x + 4 = 5 + 4 = 9

    x + 6 = 5 + 6 = 11

    ur numbers are : 5,7,9, and 11
  2. 2 July, 23:11
    0
    The answers are 5,7,9 and 11
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