Solve triangle ABC given that A=56 B=57 b=9

a) C=64, a=10.2, c=9.8

b) C=67, a=10.2, c=9.88

c) C=67, a=8.9, c=9.88

d) C=66, a=8.7, c=9.88

Sin A / a = sin B / b

sin 56 / a = sin 57 / 9

a = 9sin 56 / sin 57 = 8.9

C = 180 - 56 - 57 = 67

sin 67 / c = sin 57 / 9

c = 9sin 67 / sin 57 = 9.88

option c is the correct answer.

Sin A/a = Sin B/b

Sin 56/a = Sin 57/9

a = (Sin 56/Sin 57) x 9

a = 8.9

c) C=67, a=8.9, c=9.88