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28 December, 19:30

What are the solutions for the equation 2z^2+4z+2=0

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  1. 28 December, 20:31
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    Undistribute 2

    2 (z^2+2z+1) = 0

    factor

    2 (z+1) (z+1) = 0

    se to zero

    2=0 false

    z+1=0

    z=-1

    solution is z=-1
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