What radius of a circle is required to inscribe an equilateral triangle with an area of 15.588 in2 and an altitude of 5.196 in? (round to nearest tenth)

Area of triangle = 1/2 base x height

15.588 = 1/2 * base x 5.196

15.588 = base x 2.598

base = 15.588 / 2.598 = 6

equi center of triangle = 1/3*5.196 = 1.732

radius of circle = Sqrt (1.732^2 + 3^2) =

sqrt (2.999824 + 9) =

sqrt (11.999824) = 3.464

rounded to nearest tenth = 3.5 inches

Round it to the nearest tenth so that would be 3.5