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4 January, 20:37

the length of a rectangle is five times its width.

If the area of the rectangle is 245m^2, find its perimeter.

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Answers (2)
  1. 4 January, 20:47
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    The length of the rectangle is 35m and the width is 7m. Therefore, the perimeter is 84m.
  2. 4 January, 21:03
    0
    So lets say that the width of the rectangle is x. If the lenght of the rectange is 5 times the width of the rectangle we must multiply x by 5. So the width is x and the lenght is 5x. The area of a rectangle is found by multiplying the length and the width. So we know that

    x by 5x = 245m^2. Now we just need to work with the equation and find x.

    x (5x) = 5x ^2

    The equation is now:

    5x^2=245m^2

    Divide both sides by 5:

    x^2 = 49

    Square root both sides:

    x = 7

    Check your answer by substituting in:

    5 (7) x 7 = 245m^2

    Now we know that x = 7 so if one side is 5x that means 5 (7) = 35

    The opposite lengths of a rectangle are congruent so the other side must also be 35. This gives us 70m

    As one side is x that means one side is 7, since the opposite widths of a rectangle are congruent that means that the other side must also be 7. This gives us 14m.

    If we add 70m and 14m = 84. < - - - That is the perimeter.
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