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11 September, 00:27

Standard normal curve between z=.42 and z=1.92

a =.6902

b =.3098

c =.1902

d =.8098

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  1. 11 September, 01:59
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    The correct answer is Choice B: 0.3098.

    To find the answer, you have to use a normal distribution table. Look up the percents for each z-score and subtract them to find the region between.

    z = 1.92 the percent is 0.9726

    z = 0.42 the percent is 0.6628

    0.9726 - 0.6628 = 0.3098
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