When jill started jogging she ran 3/4 mile on the first day 1 1/8 miles on the second day and 1 1/2 miles on the third day if she increased the distance she jogged each day by the same amount how far did she jog on the fifth day? explain how you found your answer

Question

Mathematics

Guest

22 November, 04:17

When jill started jogging she ran 3/4 mile on the first day 1 1/8 miles on the second day and 1 1/2 miles on the third day if she increased the distance she jogged each day by the same amount how far did she jog on the fifth day? explain how you found your answer

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Answers (1)

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Kristopher Hayden · Answer 1

1 1/8 - 3/4 =

9/8 - 3/4 =

9/8 - 6/8 =

3/8 ... so she ran 3/8 miles per day

what u have is an arithmetic sequence with a common difference of 3/8.

And we are looking for the fifth term ...

an = a1 + d (n - 1)

n = term we want to find = 5

a1 = first term = 3/4

d = common difference = 3/8

now we sub

a (5) = 3/4 + 3/8 (5 - 1)

a (5) = 3/4 + 3/8 (4)

a (5) = 3/4 + 12/8

a (5) = 6/8 + 12/8

a (5) = 18/8 reduces to 9/4 or 2 1/4 miles < = = jogged on 5th day