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16 October, 07:21

2 sin 2θ - 3 sin θ = 0

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Answers (2)
  1. 16 October, 09:55
    0
    Sin2θ = 2sinθcosθ

    2 sin 2θ - 3 sin θ = 0

    2 (2sinθcosθ) - 3 sin θ = 0

    4sinθcosθ - 3sin θ = 0

    sinθ (4cosθ - 3) = 0

    sinθ = 0, 4cosθ - 3 = 0 cosθ = 3/4

    θ = sin⁻¹ (0) θ = cos⁻¹ (0.75)

    θ = 0, 180, 360 degrees, θ ≈ 41.41°, 360 - 41.41 = 318.59°

    θ = 0°, 180°, 360°, ≈ 41.41°, ≈ 318.59°
  2. 16 October, 11:17
    0
    (-1/4)

    ...
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