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21 September, 14:23

What are the zeros of the function f (x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = x = x = x = x =

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  1. 21 September, 14:57
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    X²+5x+5 has zeroes given by x = (-5±√25-20) / 2 = (-5±√5) / 2=-1.3820 and - 3.6180.

    In simplest radical form the zeroes are - 5/2+√5/2 and - 5/2-√5/2.
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