What is the length of the longest side of a triangle that has the vertices (2, 6), (-4, 6), and (-4, 4) ? a. 2/10 units b. 40 units c. / 10 units d. 4/10 units

Length (2, 6) to (-4, 6) is sqrt ((x2 - x1)) ^2 + (y2 - y1) ^2) = sqrt ((-4 - 2) ^2 + (6 - 6) ^2) = sqrt ((-6) ^2 + 0) = 6

Length (2, 6) to (-4, 4) is sqrt ((-4 - 2) ^2 + (4 - 6) ^2) = sqrt ((-6) ^2 + (-2) ^2) = sqrt (36 + 4) = sqrt (40) = 2sqrt (10) units

Length (-4, 6) to (-4, 4) is sqrt ((-4 - (-4)) ^2 + (4 - 6) ^2) = sqrt (0^2 + (-2) ^2) = 2

Therefore, the length of the longest side is 2sqrt (10) units