How do I solve - 5 (u-3) = 4u-3

Remember you can do anything to an equation as long as you do it to both sides

first, distribute

remember, negative times negative=positive

distributive proeprty is a (b+c) = ab+ac

so

-5 (u-3) = 4u-3

distribute

-5u+15=4u-3

add 5u to both sides

15=9u-3

add 3 to both sides

18=9u

divide both sides by 9

2=u

u=2

Use the distribution property to get - 5u+15=4u-3. Add 5u to both sides of the equation to get 15=9u-3. Add 3 to both sides of the equation to get 18=9u and then divide both sides of the equation by 9. This gives you u=2.