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27 January, 18:52

Let cos x = 1√10 with x in QIV and find: cot2x

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  1. 27 January, 21:14
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    Cos x = 1/√10

    sin x = √ (1 - 1 / 10) = √9/10 = - 3/√10 (because x is in Q IV)

    cot 2 x = cos 2 x/sin 2x = (cos²x - sin²x) / (2 sinx cosx) =

    = (1/10 - 3/10) / (2 * (-3/√10) * 1/√10) = ( - 8/10) / (-6/10) = 8/6 = 4/3
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