Ask Question
29 November, 04:39

Solve for x

1. log (x+9) = log (2x-7)

2. log (x-1) ^2=log (-5x-1)

+4
Answers (1)
  1. 29 November, 05:04
    0
    Lets first solve the first one:

    log (x+9) = log (2x-7)

    Convert the logarithmic equation to an exponential equation.

    10^ log (x+9) = 10^ log (2x-7)

    Remember that 10^ logx = x, so

    x+9=2x-7

    Move values with 'x' to the right hand side.

    7+9=2x-x

    Combine like terms.

    16=x so,

    x=16

    Check:

    log (x+9) = log (2x-7)

    If x=16

    log (16+9) = log (2 (16) - 7)

    log25 = log (32-7)

    log25 = log25

    x=16 is a solution.

    Solve the second one like i solved this one, try it
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve for x 1. log (x+9) = log (2x-7) 2. log (x-1) ^2=log (-5x-1) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers