Determine b, given that A = 63°, C = 49°, and c = 3.

A=63°

C=49°

c=3

b=?

Solution:

A+B+C=180°

63°+B+49°=180°

B+112°=180°

Solving for B:

B+112°-112°=180°-112°

B=68°

Using Law of Sines:

b/sin B = c/sin C

b/sin 68°=3/sin 49°

Solving for b:

sin 68° (b/sin 68°) = sin 68° (3/sin 49°)

b=3 sin 68°/sin 49°

sin 68°=0.927183855

sin 49°=0.754709580

b=3 (0.927183855) / 0.754709580

b=3.685591966

b=3.6856