Ask Question
22 June, 14:19

For ΔABC, ∠A = 4x - 4, ∠B = 6x - 1, and ∠C = 8x - 13. If ΔABC undergoes a dilation by a scale factor of 2 to create ΔA'B'C' with ∠A' = 51 - x, ∠B' = 4x + 21, and ∠C' = 6x + 9, which confirms that ΔABC∼ΔA'B'C by the AA criterion?

+5
Answers (1)
  1. 22 June, 15:18
    0
    4x-4+6x-1+8x-13=180 (angle sum of triangle)

    18x-18=180

    x=11

    ∠A=4*11-4=40°

    ∠B=6*11-1=65°

    ∠A' = 51-11=40°

    ∠B'=4*11+21=65°

    since ∠A = ∠A' = 40°, ∠B = ∠B'=65°

    ΔABC∼ΔA'B'C (AA)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “For ΔABC, ∠A = 4x - 4, ∠B = 6x - 1, and ∠C = 8x - 13. If ΔABC undergoes a dilation by a scale factor of 2 to create ΔA'B'C' with ∠A' = 51 - ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers