Angle DOE and angle EOF are adjacent angles. If m∠DOF = 66°, m∠DOE = x, and m∠EOF = 27°, which equation could be used to solve for x?

A.

x + 66° + 27° = 180°

B.

x - 66° + 27° = 90°

C.

x - 27° = 66°

D.

x + 27° = 66°

Question

Mathematics

Gaige Pollard

9 January, 02:44

Angle DOE and angle EOF are adjacent angles. If m∠DOF = 66°, m∠DOE = x, and m∠EOF = 27°, which equation could be used to solve for x?

A.

x + 66° + 27° = 180°

B.

x - 66° + 27° = 90°

C.

x - 27° = 66°

D.

x + 27° = 66°

+5

Answers (1)

Know the Answer?

Abril Mckenzie · Answer 1

Angle DOE and angle EOF are adjacent angles. If m∠DOF = 66°, m∠DOE = x, and m∠EOF = 27°, which equation could be used to solve for x?

D.

x + 27° = 66°

Angle DOE and angle EOF are adjacent angles. If m∠DOF = 66°, m∠DOE = x, and m∠EOF = 27°, which equation could be used to solve for x?A.x + 66° + 27° = 180°B.x - 66° + 27° = 90°C.x - 27° = 66°D.x + 27° = 66°

Angle DOE and angle EOF are adjacent angles. If m∠DOF = 66°, m∠DOE = x, and m∠EOF = 27°, which equation could be used to solve for x?

A.

x + 66° + 27° = 180°

B.

x - 66° + 27° = 90°

C.

x - 27° = 66°

D.

x + 27° = 66°