How many permutations of three items can be selected from a group of six? use the letters a, b, c, d, e, and f to identify the items, and list each of the permutations of items b, d, and f?

Number of permutations of 3 items can be selected from a group of 6

= 6P3

= / frac{6!}{3!}

= / frac{6 x 5 x 4 x 3!}{3!}

= 6 x 5 x 4

= 120

There are 120 permutations.

Permutations of items b, d and f is the different arrangement using these 3 letters & they are

bdf, bfd, dbf, dfb, fbd, fdb