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Mathematics
Valery Downs
23 May, 20:53
Factor 9x 6 - 16y 6 completely?
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Tucker Byrd
23 May, 23:26
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This is the concept of polynomial functions, we are required to factor the polynomial of degree six given by:
9x^2-16y^6
let b=y^2
such that the expression becomes;
9x^2-16b^2
9x^2-12xb+12xb-16b^2
factoring the above we get:
3x (3x-4xb) + 4b (3x-4b)
= (3x-4b) (3x+4b)
replacing b by y^2 we get:
(3x-4y^2) (3x+4y^2)
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