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17 July, 02:33

The diagram represents the factorization of a2 + 8a + 12. What is the missing number that will complete the factorization? a2 + 8a + 12 = (a + 2) (a + )

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  1. 17 July, 03:08
    0
    To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions ...

    jk=ac=12 and j+k=b=8, so j and k must be 2 and 6

    Then the factors are just (a+j) (a+k), in this case:

    (a+2) (a+6)

    So the missing term was 6
  2. 17 July, 04:37
    0
    I'm assuming the a is squared.

    You have to find what multiplies to make 12 (1st number and last multiplied together) and adds to make 8 (the middle number). In this case the two numbers you need are 2 and 6, and so your missing number is 6. If you want to check, you can multiply out the brackets. Hope I explained well enough.
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