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30 March, 15:17

I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°)

ii) How many solutions has the equation sin2x + 3cos2x = 0 for 0 < = X <=1080°?

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  1. 30 March, 18:58
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    Get rid of cos2x by dividing both the values. So Sin2x/cos2x + 3cos2x/cos2x.

    Tan2x = 3

    2x = - 71.5 so x is - 35.6

    Use the quadrant method and add 360 to the two values you get.
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