One positive number is the square of another positive number. their sum is 132. find the numbers.

X + x² = 132

x + x²-132 = 132-132

x²+x - 132 = 0

(x-11) (x+12) = 0

x-11 = 0 X+12=0

x-11+11 = 0+11 X+12-12=0-12

x = 11 x = - 12

Check

x + x² = 132 x + x² = 132

-12 + - 12² = 132 11 + 11² = 132

-12 + 144 = 132 11 + 121=132

132 = 132 132=132

Since the problem says positive the answer is (11,121)